Base | Representation |
---|---|
bin | 11001101100011011101101… |
… | …100100101010000100000011 |
3 | 112211010010120011011210202001 |
4 | 121230123231210222010003 |
5 | 104302431332243224202 |
6 | 1040201330225204431 |
7 | 32542211502664402 |
oct | 3154335544520403 |
9 | 484103504153661 |
10 | 113004575367427 |
11 | 33008a75854167 |
12 | 10811063790717 |
13 | 4b093939a5763 |
14 | 1dc9644761639 |
15 | d0e795980d87 |
hex | 66c6ed92a103 |
113004575367427 has 4 divisors (see below), whose sum is σ = 113635885844520. Its totient is φ = 112373264890336.
The previous prime is 113004575367373. The next prime is 113004575367443. The reversal of 113004575367427 is 724763575400311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113004575367427 - 235 = 112970215629059 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113004575367487) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 315655238278 + ... + 315655238635.
It is an arithmetic number, because the mean of its divisors is an integer number (28408971461130).
Almost surely, 2113004575367427 is an apocalyptic number.
113004575367427 is a deficient number, since it is larger than the sum of its proper divisors (631310477093).
113004575367427 is an equidigital number, since it uses as much as digits as its factorization.
113004575367427 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 631310477092.
The product of its (nonzero) digits is 14817600, while the sum is 55.
The spelling of 113004575367427 in words is "one hundred thirteen trillion, four billion, five hundred seventy-five million, three hundred sixty-seven thousand, four hundred twenty-seven".
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