Base | Representation |
---|---|
bin | 1010010001110001110011… |
… | …0011101000010011001011 |
3 | 1111000022200012220222021122 |
4 | 2210130130303220103023 |
5 | 2440122002304032420 |
6 | 40011221503025455 |
7 | 2244302654161205 |
oct | 244343463502313 |
9 | 44008605828248 |
10 | 11300542252235 |
11 | 3667595551355 |
12 | 132615489b28b |
13 | 63c8376ac772 |
14 | 2b0d4070b775 |
15 | 148e4677a725 |
hex | a471cce84cb |
11300542252235 has 8 divisors (see below), whose sum is σ = 13630913142720. Its totient is φ = 8993592175104.
The previous prime is 11300542252229. The next prime is 11300542252249. The reversal of 11300542252235 is 53225224500311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11300542252235 - 26 = 11300542252171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11300542252195 and 11300542252204.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5855202275 + ... + 5855204204.
It is an arithmetic number, because the mean of its divisors is an integer number (1703864142840).
Almost surely, 211300542252235 is an apocalyptic number.
11300542252235 is a deficient number, since it is larger than the sum of its proper divisors (2330370890485).
11300542252235 is a wasteful number, since it uses less digits than its factorization.
11300542252235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11710406677.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 11300542252235 its reverse (53225224500311), we get a palindrome (64525766752546).
The spelling of 11300542252235 in words is "eleven trillion, three hundred billion, five hundred forty-two million, two hundred fifty-two thousand, two hundred thirty-five".
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