1130161331731 has 4 divisors (see below), whose sum is σ = 1149316608600. Its totient is φ = 1111006054864.

The previous prime is 1130161331711. The next prime is 1130161331773. The reversal of 1130161331731 is 1371331610311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1130161331731 - 2¹³ = 1130161323539 is a prime.

It is a super-2 number, since 2×1130161331731² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1130161331693 and 1130161331702.

It is not an unprimeable number, because it can be changed into a prime (1130161331701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9577638346 + ... + 9577638463.

It is an arithmetic number, because the mean of its divisors is an integer number (287329152150).

Almost surely, 2^{1130161331731} is an apocalyptic number.

1130161331731 is a deficient number, since it is larger than the sum of its proper divisors (19155276869).

1130161331731 is an equidigital number, since it uses as much as digits as its factorization.

1130161331731 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19155276868.

The product of its (nonzero) digits is 3402, while the sum is 31.

The spelling of 1130161331731 in words is "one trillion, one hundred thirty billion, one hundred sixty-one million, three hundred thirty-one thousand, seven hundred thirty-one".