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11302030113 = 311342485761
BaseRepresentation
bin10101000011010011…
…10100101100100001
31002011122202121122220
422201221310230201
5141121304430423
65105253421253
7550034446053
oct124151645441
932148677586
1011302030113
11487a779560
12223503a829
1310b16864aa
147930518d3
1546234e9e3
hex2a1a74b21

11302030113 has 8 divisors (see below), whose sum is σ = 16439316576. Its totient is φ = 6849715200.

The previous prime is 11302030057. The next prime is 11302030123. The reversal of 11302030113 is 31103020311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11302030113 - 233 = 2712095521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11302030092 and 11302030101.

It is not an unprimeable number, because it can be changed into a prime (11302030123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 171242848 + ... + 171242913.

It is an arithmetic number, because the mean of its divisors is an integer number (2054914572).

Almost surely, 211302030113 is an apocalyptic number.

It is an amenable number.

11302030113 is a deficient number, since it is larger than the sum of its proper divisors (5137286463).

11302030113 is a wasteful number, since it uses less digits than its factorization.

11302030113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 342485775.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11302030113 its reverse (31103020311), we get a palindrome (42405050424).

The spelling of 11302030113 in words is "eleven billion, three hundred two million, thirty thousand, one hundred thirteen".

Divisors: 1 3 11 33 342485761 1027457283 3767343371 11302030113