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1130213003 = 7115918493
BaseRepresentation
bin100001101011101…
…1010111010001011
32220202200202202212
41003113122322023
54303313304003
6304052215335
740002436433
oct10327327213
92822622685
101130213003
1152aa80837
1227660a54b
131501cb8ba
14aa1652c3
1569352dd8
hex435dae8b

1130213003 has 4 divisors (see below), whose sum is σ = 1146131568. Its totient is φ = 1114294440.

The previous prime is 1130212997. The next prime is 1130213033. The reversal of 1130213003 is 3003120311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1130213003 - 24 = 1130212987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1130213033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7959176 + ... + 7959317.

It is an arithmetic number, because the mean of its divisors is an integer number (286532892).

Almost surely, 21130213003 is an apocalyptic number.

1130213003 is a deficient number, since it is larger than the sum of its proper divisors (15918565).

1130213003 is an equidigital number, since it uses as much as digits as its factorization.

1130213003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15918564.

The product of its (nonzero) digits is 54, while the sum is 14.

The square root of 1130213003 is about 33618.6407072029. The cubic root of 1130213003 is about 1041.6458785512.

Adding to 1130213003 its reverse (3003120311), we get a palindrome (4133333314).

The spelling of 1130213003 in words is "one billion, one hundred thirty million, two hundred thirteen thousand, three".

Divisors: 1 71 15918493 1130213003