Base | Representation |
---|---|
bin | 110100101000010100… |
… | …0101110000011111011 |
3 | 101210201200211112221222 |
4 | 1221100220232003323 |
5 | 3322432113021103 |
6 | 123531021422255 |
7 | 11110535106113 |
oct | 1512050560373 |
9 | 353650745858 |
10 | 113022001403 |
11 | 43a28a78533 |
12 | 19aa2a0a98b |
13 | a87261580c |
14 | 56826b6043 |
15 | 2e17585638 |
hex | 1a50a2e0fb |
113022001403 has 8 divisors (see below), whose sum is σ = 121740389376. Its totient is φ = 104620645800.
The previous prime is 113022001387. The next prime is 113022001447. The reversal of 113022001403 is 304100220311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113022001403 - 24 = 113022001387 is a prime.
It is a super-2 number, since 2×1130220014032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113022009403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 79257353 + ... + 79258778.
It is an arithmetic number, because the mean of its divisors is an integer number (15217548672).
Almost surely, 2113022001403 is an apocalyptic number.
113022001403 is a deficient number, since it is larger than the sum of its proper divisors (8718387973).
113022001403 is a wasteful number, since it uses less digits than its factorization.
113022001403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158516185.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 113022001403 its reverse (304100220311), we get a palindrome (417122221714).
The spelling of 113022001403 in words is "one hundred thirteen billion, twenty-two million, one thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •