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1130221115 = 51761217979
BaseRepresentation
bin100001101011101…
…1100111000111011
32220202201011220022
41003113130320323
54303314033430
6304052321055
740002502202
oct10327347073
92822634808
101130221115
1152aa86941
1227661318b
131502024ba
14aa168239
15693554e5
hex435dce3b

1130221115 has 16 divisors (see below), whose sum is σ = 1459594080. Its totient is φ = 837035520.

The previous prime is 1130221087. The next prime is 1130221117. The reversal of 1130221115 is 5111220311.

It is not a de Polignac number, because 1130221115 - 28 = 1130220859 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a junction number, because it is equal to n+sod(n) for n = 1130221093 and 1130221102.

It is not an unprimeable number, because it can be changed into a prime (1130221117) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 103805 + ... + 114174.

It is an arithmetic number, because the mean of its divisors is an integer number (91224630).

Almost surely, 21130221115 is an apocalyptic number.

1130221115 is a deficient number, since it is larger than the sum of its proper divisors (329372965).

1130221115 is a wasteful number, since it uses less digits than its factorization.

1130221115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 218062.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 1130221115 is about 33618.7613543390. The cubic root of 1130221115 is about 1041.6483706511.

Adding to 1130221115 its reverse (5111220311), we get a palindrome (6241441426).

The spelling of 1130221115 in words is "one billion, one hundred thirty million, two hundred twenty-one thousand, one hundred fifteen".

Divisors: 1 5 17 61 85 305 1037 5185 217979 1089895 3705643 13296719 18528215 66483595 226044223 1130221115