Base | Representation |
---|---|
bin | 110100101000010100… |
… | …1001011000011000011 |
3 | 101210201201001120211022 |
4 | 1221100221023003003 |
5 | 3322432130321011 |
6 | 123531024140055 |
7 | 11110536112214 |
oct | 1512051130303 |
9 | 353651046738 |
10 | 113022120131 |
11 | 43a29049758 |
12 | 19aa2a6762b |
13 | a87265787b |
14 | 568270740b |
15 | 2e175aa8db |
hex | 1a50a4b0c3 |
113022120131 has 4 divisors (see below), whose sum is σ = 113780658000. Its totient is φ = 112263582264.
The previous prime is 113022120109. The next prime is 113022120161. The reversal of 113022120131 is 131021220311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113022120131 - 222 = 113017925827 is a prime.
It is a super-2 number, since 2×1130221201312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113022120161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 379268711 + ... + 379269008.
It is an arithmetic number, because the mean of its divisors is an integer number (28445164500).
Almost surely, 2113022120131 is an apocalyptic number.
113022120131 is a deficient number, since it is larger than the sum of its proper divisors (758537869).
113022120131 is an equidigital number, since it uses as much as digits as its factorization.
113022120131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 758537868.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 113022120131 its reverse (131021220311), we get a palindrome (244043340442).
The spelling of 113022120131 in words is "one hundred thirteen billion, twenty-two million, one hundred twenty thousand, one hundred thirty-one".
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