113023111313 has 4 divisors (see below), whose sum is σ = 129169270080. Its totient is φ = 96876952548.

The previous prime is 113023111309. The next prime is 113023111319. The reversal of 113023111313 is 313111320311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 313111320311 = 41 ⋅7636861471.

It is a cyclic number.

It is not a de Polignac number, because 113023111313 - 2² = 113023111309 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113023111319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8073079373 + ... + 8073079386.

It is an arithmetic number, because the mean of its divisors is an integer number (32292317520).

Almost surely, 2^113023111313 is an apocalyptic number.

It is an amenable number.

113023111313 is a deficient number, since it is larger than the sum of its proper divisors (16146158767).

113023111313 is an equidigital number, since it uses as much as digits as its factorization.

113023111313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16146158766.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 113023111313 its reverse (313111320311), we get a palindrome (426134431624).

The spelling of 113023111313 in words is "one hundred thirteen billion, twenty-three million, one hundred eleven thousand, three hundred thirteen".