Base | Representation |
---|---|
bin | 11001101100101100111110… |
… | …111011100111100001111011 |
3 | 112211011220102120120102022212 |
4 | 121230230332323213201323 |
5 | 104303232322233210133 |
6 | 1040214034333405335 |
7 | 32543436165361061 |
oct | 3154547673474173 |
9 | 484156376512285 |
10 | 113023120210043 |
11 | 3301592194097a |
12 | 1081477a33984b |
13 | 4b0b05aa5bc04 |
14 | 1dca4c3698031 |
15 | d0eecdaae148 |
hex | 66cb3eee787b |
113023120210043 has 4 divisors (see below), whose sum is σ = 113138097952848. Its totient is φ = 112908142467240.
The previous prime is 113023120210031. The next prime is 113023120210057. The reversal of 113023120210043 is 340012021320311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113023120210043 - 210 = 113023120209019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113023120210003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57488869928 + ... + 57488871893.
It is an arithmetic number, because the mean of its divisors is an integer number (28284524488212).
Almost surely, 2113023120210043 is an apocalyptic number.
113023120210043 is a deficient number, since it is larger than the sum of its proper divisors (114977742805).
113023120210043 is an equidigital number, since it uses as much as digits as its factorization.
113023120210043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114977742804.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 113023120210043 its reverse (340012021320311), we get a palindrome (453035141530354).
The spelling of 113023120210043 in words is "one hundred thirteen trillion, twenty-three billion, one hundred twenty million, two hundred ten thousand, forty-three".
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