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1130233243403 = 11516719885519
BaseRepresentation
bin10000011100100111001…
…001101010011100001011
311000001022220020122220102
4100130213021222130023
5122004204202242103
62223115540520015
7144441143025215
oct20344711523413
94001286218812
101130233243403
113a6369223270
121630689b000b
1382771596a04
143c9bc8a95b5
151e5eecede88
hex1072726a70b

1130233243403 has 8 divisors (see below), whose sum is σ = 1233220408320. Its totient is φ = 1027285859880.

The previous prime is 1130233243343. The next prime is 1130233243421. The reversal of 1130233243403 is 3043423320311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1130233243403 - 210 = 1130233242379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1130233243303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9885923 + ... + 9999596.

It is an arithmetic number, because the mean of its divisors is an integer number (154152551040).

Almost surely, 21130233243403 is an apocalyptic number.

1130233243403 is a deficient number, since it is larger than the sum of its proper divisors (102987164917).

1130233243403 is a wasteful number, since it uses less digits than its factorization.

1130233243403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19890697.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 1130233243403 its reverse (3043423320311), we get a palindrome (4173656563714).

The spelling of 1130233243403 in words is "one trillion, one hundred thirty billion, two hundred thirty-three million, two hundred forty-three thousand, four hundred three".

Divisors: 1 11 5167 56837 19885519 218740709 102748476673 1130233243403