1130244423131 has 4 divisors (see below), whose sum is σ = 1131224688312. Its totient is φ = 1129264157952.

The previous prime is 1130244423073. The next prime is 1130244423137. The reversal of 1130244423131 is 1313244420311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1130244423131 - 2¹⁸ = 1130244160987 is a prime.

It is a super-2 number, since 2×1130244423131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1130244423094 and 1130244423103.

It is not an unprimeable number, because it can be changed into a prime (1130244423137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 490130861 + ... + 490133166.

It is an arithmetic number, because the mean of its divisors is an integer number (282806172078).

Almost surely, 2^{1130244423131} is an apocalyptic number.

1130244423131 is a deficient number, since it is larger than the sum of its proper divisors (980265181).

1130244423131 is an equidigital number, since it uses as much as digits as its factorization.

1130244423131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 980265180.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1130244423131 its reverse (1313244420311), we get a palindrome (2443488843442).

The spelling of 1130244423131 in words is "one trillion, one hundred thirty billion, two hundred forty-four million, four hundred twenty-three thousand, one hundred thirty-one".