Base | Representation |
---|---|
bin | 10101000011011011… |
… | …11010011011111001 |
3 | 1002011201210002021212 |
4 | 22201231322123321 |
5 | 141122043232301 |
6 | 5105332412505 |
7 | 550046532506 |
oct | 124155723371 |
9 | 32151702255 |
10 | 11303102201 |
11 | 4880340a86 |
12 | 2235477135 |
13 | 10b1970471 |
14 | 7932504ad |
15 | 4624b24bb |
hex | 2a1b7a6f9 |
11303102201 has 4 divisors (see below), whose sum is σ = 11303343504. Its totient is φ = 11302860900.
The previous prime is 11303102191. The next prime is 11303102207. The reversal of 11303102201 is 10220130311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10220130311 = 41 ⋅249271471.
It is a cyclic number.
It is not a de Polignac number, because 11303102201 - 218 = 11302840057 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (11303102207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25235 + ... + 152456.
It is an arithmetic number, because the mean of its divisors is an integer number (2825835876).
Almost surely, 211303102201 is an apocalyptic number.
It is an amenable number.
11303102201 is a deficient number, since it is larger than the sum of its proper divisors (241303).
11303102201 is an equidigital number, since it uses as much as digits as its factorization.
11303102201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 241302.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 11303102201 its reverse (10220130311), we get a palindrome (21523232512).
The spelling of 11303102201 in words is "eleven billion, three hundred three million, one hundred two thousand, two hundred one".
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