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11303112131 = 72383156157
BaseRepresentation
bin10101000011011011…
…11100110111000011
31002011201210120220122
422201231330313003
5141122044042011
65105332530455
7550046603453
oct124155746703
932151716818
1011303112131
114880348493
122235480a2b
1310b1974b3c
14793253d63
154624b53db
hex2a1b7cdc3

11303112131 has 4 divisors (see below), whose sum is σ = 11303340672. Its totient is φ = 11302883592.

The previous prime is 11303112083. The next prime is 11303112251. The reversal of 11303112131 is 13121130311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13121130311 = 53992430289.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11303112131 is a prime.

It is a super-2 number, since 2×113031121312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11303112731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5696 + ... + 150461.

It is an arithmetic number, because the mean of its divisors is an integer number (2825835168).

Almost surely, 211303112131 is an apocalyptic number.

11303112131 is a deficient number, since it is larger than the sum of its proper divisors (228541).

11303112131 is an equidigital number, since it uses as much as digits as its factorization.

11303112131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 228540.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11303112131 its reverse (13121130311), we get a palindrome (24424242442).

The spelling of 11303112131 in words is "eleven billion, three hundred three million, one hundred twelve thousand, one hundred thirty-one".

Divisors: 1 72383 156157 11303112131