Base | Representation |
---|---|
bin | 11001101100110100100111… |
… | …101111001011111101010001 |
3 | 112211012200121002211012222122 |
4 | 121230310213233023331101 |
5 | 104303401121134310001 |
6 | 1040221512205144025 |
7 | 32544146335126622 |
oct | 3154644757137521 |
9 | 484180532735878 |
10 | 113031321010001 |
11 | 3301934aa982a9 |
12 | 1081628885b015 |
13 | 4b0ba66a79474 |
14 | 1dcaa608b1a49 |
15 | d1030da20b1b |
hex | 66cd27bcbf51 |
113031321010001 has 8 divisors (see below), whose sum is σ = 114306854457600. Its totient is φ = 111755910198240.
The previous prime is 113031321009967. The next prime is 113031321010081. The reversal of 113031321010001 is 100010123130311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113031321010001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113031321010081) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28804565 + ... + 32492546.
It is an arithmetic number, because the mean of its divisors is an integer number (14288356807200).
Almost surely, 2113031321010001 is an apocalyptic number.
It is an amenable number.
113031321010001 is a deficient number, since it is larger than the sum of its proper divisors (1275533447599).
113031321010001 is an equidigital number, since it uses as much as digits as its factorization.
113031321010001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61317919.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113031321010001 its reverse (100010123130311), we get a palindrome (213041444140312).
The spelling of 113031321010001 in words is "one hundred thirteen trillion, thirty-one billion, three hundred twenty-one million, ten thousand, one".
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