Base | Representation |
---|---|
bin | 10101000011011100… |
… | …11010011001101011 |
3 | 1002011202000201220010 |
4 | 22201232122121223 |
5 | 141122111430011 |
6 | 5105335303003 |
7 | 550050616311 |
oct | 124156323153 |
9 | 32152021803 |
10 | 11303233131 |
11 | 4880420393 |
12 | 223551aa63 |
13 | 10b19b7c38 |
14 | 7932860b1 |
15 | 4624db1a6 |
hex | 2a1b9a66b |
11303233131 has 4 divisors (see below), whose sum is σ = 15070977512. Its totient is φ = 7535488752.
The previous prime is 11303233103. The next prime is 11303233153. The reversal of 11303233131 is 13133230311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13133230311 = 3 ⋅4377743437.
It is not a de Polignac number, because 11303233131 - 222 = 11299038827 is a prime.
It is a super-2 number, since 2×113032331312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11303233098 and 11303233107.
It is not an unprimeable number, because it can be changed into a prime (11303233031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1883872186 + ... + 1883872191.
It is an arithmetic number, because the mean of its divisors is an integer number (3767744378).
Almost surely, 211303233131 is an apocalyptic number.
11303233131 is a deficient number, since it is larger than the sum of its proper divisors (3767744381).
11303233131 is an equidigital number, since it uses as much as digits as its factorization.
11303233131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3767744380.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 11303233131 its reverse (13133230311), we get a palindrome (24436463442).
The spelling of 11303233131 in words is "eleven billion, three hundred three million, two hundred thirty-three thousand, one hundred thirty-one".
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