Base | Representation |
---|---|
bin | 100001101011111… |
… | …1101010111101001 |
3 | 2220202221221101122 |
4 | 1003113331113221 |
5 | 4303332313103 |
6 | 304055225025 |
7 | 40003565105 |
oct | 10327752751 |
9 | 2822857348 |
10 | 1130354153 |
11 | 530067895 |
12 | 276678175 |
13 | 15024ac16 |
14 | aa1a0905 |
15 | 6937eb38 |
hex | 435fd5e9 |
1130354153 has 4 divisors (see below), whose sum is σ = 1134857808. Its totient is φ = 1125850500.
The previous prime is 1130354129. The next prime is 1130354171. The reversal of 1130354153 is 3514530311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1130354153 - 28 = 1130353897 is a prime.
It is a super-2 number, since 2×11303541532 = 2555401022408694818, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1130350153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2251451 + ... + 2251952.
It is an arithmetic number, because the mean of its divisors is an integer number (283714452).
Almost surely, 21130354153 is an apocalyptic number.
It is an amenable number.
1130354153 is a deficient number, since it is larger than the sum of its proper divisors (4503655).
1130354153 is an equidigital number, since it uses as much as digits as its factorization.
1130354153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4503654.
The product of its (nonzero) digits is 2700, while the sum is 26.
The square root of 1130354153 is about 33620.7399234461. The cubic root of 1130354153 is about 1041.6892397569.
Adding to 1130354153 its reverse (3514530311), we get a palindrome (4644884464).
It can be divided in two parts, 11303 and 54153, that added together give a palindrome (65456).
The spelling of 1130354153 in words is "one billion, one hundred thirty million, three hundred fifty-four thousand, one hundred fifty-three".
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