113040311020121 has 4 divisors (see below), whose sum is σ = 113238280041744. Its totient is φ = 112842341998500.

The previous prime is 113040311020093. The next prime is 113040311020157. The reversal of 113040311020121 is 121020113040311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113040311020121 is a prime.

It is a super-3 number, since 3×113040311020121³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 113040311020093 and 113040311020102.

It is not an unprimeable number, because it can be changed into a prime (113040311020171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 98984509955 + ... + 98984511096.

It is an arithmetic number, because the mean of its divisors is an integer number (28309570010436).

Almost surely, 2^{113040311020121} is an apocalyptic number.

It is an amenable number.

113040311020121 is a deficient number, since it is larger than the sum of its proper divisors (197969021623).

113040311020121 is an equidigital number, since it uses as much as digits as its factorization.

113040311020121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 197969021622.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 113040311020121 its reverse (121020113040311), we get a palindrome (234060424060432).

The spelling of 113040311020121 in words is "one hundred thirteen trillion, forty billion, three hundred eleven million, twenty thousand, one hundred twenty-one".