11304414240331 has 4 divisors (see below), whose sum is σ = 11310488618464. Its totient is φ = 11298339862200.

The previous prime is 11304414240307. The next prime is 11304414240341. The reversal of 11304414240331 is 13304241440311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11304414240331 is a prime.

It is a super-3 number, since 3×11304414240331³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11304414240293 and 11304414240302.

It is not an unprimeable number, because it can be changed into a prime (11304414240341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3037186275 + ... + 3037189996.

It is an arithmetic number, because the mean of its divisors is an integer number (2827622154616).

Almost surely, 2^{11304414240331} is an apocalyptic number.

11304414240331 is a deficient number, since it is larger than the sum of its proper divisors (6074378133).

11304414240331 is an equidigital number, since it uses as much as digits as its factorization.

11304414240331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6074378132.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 11304414240331 its reverse (13304241440311), we get a palindrome (24608655680642).

The spelling of 11304414240331 in words is "eleven trillion, three hundred four billion, four hundred fourteen million, two hundred forty thousand, three hundred thirty-one".