Base | Representation |
---|---|
bin | 10101000011101101… |
… | …01011100000001011 |
3 | 1002011220002211201210 |
4 | 22201312223200023 |
5 | 141123140302311 |
6 | 5105453544203 |
7 | 550105213551 |
oct | 124166534013 |
9 | 32156084653 |
10 | 11305400331 |
11 | 4881670665 |
12 | 22361a5063 |
13 | 10b22964c4 |
14 | 79368bbd1 |
15 | 4627b83a6 |
hex | 2a1dab80b |
11305400331 has 4 divisors (see below), whose sum is σ = 15073867112. Its totient is φ = 7536933552.
The previous prime is 11305400303. The next prime is 11305400371. The reversal of 11305400331 is 13300450311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13300450311 = 3 ⋅4433483437.
It is not a de Polignac number, because 11305400331 - 210 = 11305399307 is a prime.
It is a super-2 number, since 2×113054003312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11305400298 and 11305400307.
It is not an unprimeable number, because it can be changed into a prime (11305400371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1884233386 + ... + 1884233391.
It is an arithmetic number, because the mean of its divisors is an integer number (3768466778).
Almost surely, 211305400331 is an apocalyptic number.
11305400331 is a deficient number, since it is larger than the sum of its proper divisors (3768466781).
11305400331 is an equidigital number, since it uses as much as digits as its factorization.
11305400331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3768466780.
The product of its (nonzero) digits is 540, while the sum is 21.
Adding to 11305400331 its reverse (13300450311), we get a palindrome (24605850642).
The spelling of 11305400331 in words is "eleven billion, three hundred five million, four hundred thousand, three hundred thirty-one".
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