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11310000113131 = 194791712422797
BaseRepresentation
bin1010010010010101000010…
…0010100000010111101011
31111001020002100120002100221
42210211100202200113223
52440300340012110011
640015424201510511
72245056226521526
oct244452042402753
944036070502327
1011310000113131
1136705a9238215
121327b541a2437
136406b3c7c765
142b159a869bbd
151492ebc49971
hexa49508a05eb

11310000113131 has 8 divisors (see below), whose sum is σ = 11905512691280. Its totient is φ = 10714512476448.

The previous prime is 11310000113099. The next prime is 11310000113149. The reversal of 11310000113131 is 13131100001311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11310000113131 - 25 = 11310000113099 is a prime.

It is a super-2 number, since 2×113100001131312 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11310000113161) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5300976 + ... + 7121821.

It is an arithmetic number, because the mean of its divisors is an integer number (1488189086410).

Almost surely, 211310000113131 is an apocalyptic number.

11310000113131 is a deficient number, since it is larger than the sum of its proper divisors (595512578149).

11310000113131 is a wasteful number, since it uses less digits than its factorization.

11310000113131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12470733.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 11310000113131 its reverse (13131100001311), we get a palindrome (24441100114442).

The spelling of 11310000113131 in words is "eleven trillion, three hundred ten billion, one hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 19 47917 910423 12422797 236033143 595263163849 11310000113131