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1131000240433 = 71263712785587
BaseRepresentation
bin10000011101010100110…
…111100001100100110001
311000010022100111011000211
4100131110313201210301
5122012242030143213
62223324020144121
7144466145265160
oct20352467414461
94003270434024
101131000240433
113a6722172508
12163241838041
1382864462acb
143ca526c33d7
151e64730753d
hex10754de1931

1131000240433 has 8 divisors (see below), whose sum is σ = 1292674089152. Its totient is φ = 969351988176.

The previous prime is 1131000240371. The next prime is 1131000240451. The reversal of 1131000240433 is 3340420001311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1131000240433 - 29 = 1131000239921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131000243433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6304335 + ... + 6481252.

It is an arithmetic number, because the mean of its divisors is an integer number (161584261144).

Almost surely, 21131000240433 is an apocalyptic number.

It is an amenable number.

1131000240433 is a deficient number, since it is larger than the sum of its proper divisors (161673848719).

1131000240433 is a wasteful number, since it uses less digits than its factorization.

1131000240433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12798231.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 1131000240433 its reverse (3340420001311), we get a palindrome (4471420241744).

The spelling of 1131000240433 in words is "one trillion, one hundred thirty-one billion, two hundred forty thousand, four hundred thirty-three".

Divisors: 1 7 12637 88459 12785587 89499109 161571462919 1131000240433