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11310012203113 = 1329139215827571
BaseRepresentation
bin1010010010010101000101…
…0000101000000001101001
31111001020010012022022201001
42210211101100220001221
52440300401110444423
640015425312555001
72245056434344351
oct244452120500151
944036105268631
1011310012203113
113670605045638
121327b58252a61
136406b66236b0
142b159c2d5b61
151492ecd36cad
hexa4951428069

11310012203113 has 16 divisors (see below), whose sum is σ = 12690661233600. Its totient is φ = 10007492765760.

The previous prime is 11310012203051. The next prime is 11310012203123. The reversal of 11310012203113 is 31130221001311.

It is a de Polignac number, because none of the positive numbers 2k-11310012203113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11310012203123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 107861383 + ... + 107966188.

It is an arithmetic number, because the mean of its divisors is an integer number (793166327100).

Almost surely, 211310012203113 is an apocalyptic number.

11310012203113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11310012203113 is a deficient number, since it is larger than the sum of its proper divisors (1380649030487).

11310012203113 is a wasteful number, since it uses less digits than its factorization.

11310012203113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 215827752.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 11310012203113 its reverse (31130221001311), we get a palindrome (42440233204424).

The spelling of 11310012203113 in words is "eleven trillion, three hundred ten billion, twelve million, two hundred three thousand, one hundred thirteen".

Divisors: 1 13 29 139 377 1807 4031 52403 215827571 2805758423 6258999559 30000032369 81366994267 390000420797 870000938701 11310012203113