Base | Representation |
---|---|
bin | 10101000100010000… |
… | …10011011000010001 |
3 | 1002012012210112212211 |
4 | 22202020103120101 |
5 | 141130331120423 |
6 | 5110140552121 |
7 | 550162404400 |
oct | 124210233021 |
9 | 32165715784 |
10 | 11310020113 |
11 | 4884236567 |
12 | 2237852641 |
13 | 10b32231c2 |
14 | 794131637 |
15 | 462dcc10d |
hex | 2a2213611 |
11310020113 has 12 divisors (see below), whose sum is σ = 13163079540. Its totient is φ = 9689494752.
The previous prime is 11310020081. The next prime is 11310020131. The reversal of 11310020113 is 31102001311.
It can be written as a sum of positive squares in 2 ways, for example, as 7098399504 + 4211620609 = 84252^2 + 64897^2 .
It is not a de Polignac number, because 11310020113 - 25 = 11310020081 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11310020093 and 11310020102.
It is not an unprimeable number, because it can be changed into a prime (11310020143) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 44383 + ... + 156811.
It is an arithmetic number, because the mean of its divisors is an integer number (1096923295).
Almost surely, 211310020113 is an apocalyptic number.
It is an amenable number.
11310020113 is a deficient number, since it is larger than the sum of its proper divisors (1853059427).
11310020113 is a wasteful number, since it uses less digits than its factorization.
11310020113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 114496 (or 114489 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 11310020113 its reverse (31102001311), we get a palindrome (42412021424).
The spelling of 11310020113 in words is "eleven billion, three hundred ten million, twenty thousand, one hundred thirteen".
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