11310112033 has 4 divisors (see below), whose sum is σ = 12338304048. Its totient is φ = 10281920020.

The previous prime is 11310112001. The next prime is 11310112043. The reversal of 11310112033 is 33021101311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11310112033 - 2⁵ = 11310112001 is a prime.

It is a super-2 number, since 2×11310112033² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11310111998 and 11310112016.

It is not an unprimeable number, because it can be changed into a prime (11310112043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 514095991 + ... + 514096012.

It is an arithmetic number, because the mean of its divisors is an integer number (3084576012).

Almost surely, 2^11310112033 is an apocalyptic number.

It is an amenable number.

11310112033 is a deficient number, since it is larger than the sum of its proper divisors (1028192015).

11310112033 is a wasteful number, since it uses less digits than its factorization.

11310112033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1028192014.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11310112033 its reverse (33021101311), we get a palindrome (44331213344).

The spelling of 11310112033 in words is "eleven billion, three hundred ten million, one hundred twelve thousand, thirty-three".