1131012142401 has 4 divisors (see below), whose sum is σ = 1508016189872. Its totient is φ = 754008094932.

The previous prime is 1131012142399. The next prime is 1131012142427. The reversal of 1131012142401 is 1042412101311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1131012142401 - 2¹ = 1131012142399 is a prime.

It is a super-3 number, since 3×1131012142401³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131012142301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188502023731 + ... + 188502023736.

It is an arithmetic number, because the mean of its divisors is an integer number (377004047468).

Almost surely, 2^{1131012142401} is an apocalyptic number.

It is an amenable number.

1131012142401 is a deficient number, since it is larger than the sum of its proper divisors (377004047471).

1131012142401 is an equidigital number, since it uses as much as digits as its factorization.

1131012142401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 377004047470.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 1131012142401 its reverse (1042412101311), we get a palindrome (2173424243712).

The spelling of 1131012142401 in words is "one trillion, one hundred thirty-one billion, twelve million, one hundred forty-two thousand, four hundred one".