1131012321113 has 4 divisors (see below), whose sum is σ = 1167496589568. Its totient is φ = 1094528052660.

The previous prime is 1131012321059. The next prime is 1131012321209. The reversal of 1131012321113 is 3111232101311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1131012321113 is a prime.

It is a super-7 number, since 7×1131012321113⁷ (a number of 86 digits) contains 7777777 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131012326113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18242134181 + ... + 18242134242.

It is an arithmetic number, because the mean of its divisors is an integer number (291874147392).

Almost surely, 2^{1131012321113} is an apocalyptic number.

It is an amenable number.

1131012321113 is a deficient number, since it is larger than the sum of its proper divisors (36484268455).

1131012321113 is an equidigital number, since it uses as much as digits as its factorization.

1131012321113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36484268454.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 1131012321113 its reverse (3111232101311), we get a palindrome (4242244422424).

The spelling of 1131012321113 in words is "one trillion, one hundred thirty-one billion, twelve million, three hundred twenty-one thousand, one hundred thirteen".