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113101233131 = 167677252893
BaseRepresentation
bin110100101010101011…
…0111101101111101011
3101210221012220221110102
41221111112331233223
53323112403430011
6123542531540015
711112516422315
oct1512526755753
9353835827412
10113101233131
1143a697744a7
1219b0545a60b
13a885b672b3
14568d01c7b5
152e1e4d673b
hex1a555bdbeb

113101233131 has 4 divisors (see below), whose sum is σ = 113778486192. Its totient is φ = 112423980072.

The previous prime is 113101233107. The next prime is 113101233211. The reversal of 113101233131 is 131332101311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113101233131 - 26 = 113101233067 is a prime.

It is a super-2 number, since 2×1131012331312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113101230131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 338626280 + ... + 338626613.

It is an arithmetic number, because the mean of its divisors is an integer number (28444621548).

Almost surely, 2113101233131 is an apocalyptic number.

113101233131 is a deficient number, since it is larger than the sum of its proper divisors (677253061).

113101233131 is an equidigital number, since it uses as much as digits as its factorization.

113101233131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 677253060.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 113101233131 its reverse (131332101311), we get a palindrome (244433334442).

The spelling of 113101233131 in words is "one hundred thirteen billion, one hundred one million, two hundred thirty-three thousand, one hundred thirty-one".

Divisors: 1 167 677252893 113101233131