Base | Representation |
---|---|
bin | 10101000100010010… |
… | …00010000011101001 |
3 | 1002012020011021011000 |
4 | 22202021002003221 |
5 | 141130403230210 |
6 | 5110145025213 |
7 | 550164131661 |
oct | 124211020351 |
9 | 32166137130 |
10 | 11310211305 |
11 | 4884357178 |
12 | 2237925209 |
13 | 10b328c233 |
14 | 7941811a1 |
15 | 462e18ac0 |
hex | 2a22420e9 |
11310211305 has 16 divisors (see below), whose sum is σ = 20107042560. Its totient is φ = 6032112624.
The previous prime is 11310211243. The next prime is 11310211327. The reversal of 11310211305 is 50311201311.
It is not a de Polignac number, because 11310211305 - 211 = 11310209257 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41889537 + ... + 41889806.
It is an arithmetic number, because the mean of its divisors is an integer number (1256690160).
Almost surely, 211310211305 is an apocalyptic number.
11310211305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11310211305 is a deficient number, since it is larger than the sum of its proper divisors (8796831255).
11310211305 is an equidigital number, since it uses as much as digits as its factorization.
11310211305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83779357 (or 83779351 counting only the distinct ones).
The product of its (nonzero) digits is 90, while the sum is 18.
Adding to 11310211305 its reverse (50311201311), we get a palindrome (61621412616).
The spelling of 11310211305 in words is "eleven billion, three hundred ten million, two hundred eleven thousand, three hundred five".
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