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11310243401 = 67168809603
BaseRepresentation
bin10101000100010010…
…01001111001001001
31002012020012220011202
422202021021321021
5141130410242101
65110145433545
7550164324362
oct124211117111
932166186152
1011310243401
1148843792a6
12223793b8b5
1310b32a0a22
1479418cb69
15462e2336b
hex2a2249e49

11310243401 has 4 divisors (see below), whose sum is σ = 11479053072. Its totient is φ = 11141433732.

The previous prime is 11310243389. The next prime is 11310243457. The reversal of 11310243401 is 10434201311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11310243401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11310213401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84404735 + ... + 84404868.

It is an arithmetic number, because the mean of its divisors is an integer number (2869763268).

Almost surely, 211310243401 is an apocalyptic number.

It is an amenable number.

11310243401 is a deficient number, since it is larger than the sum of its proper divisors (168809671).

11310243401 is an equidigital number, since it uses as much as digits as its factorization.

11310243401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 168809670.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 11310243401 its reverse (10434201311), we get a palindrome (21744444712).

The spelling of 11310243401 in words is "eleven billion, three hundred ten million, two hundred forty-three thousand, four hundred one".

Divisors: 1 67 168809603 11310243401