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1131031111201 = 2311489411991
BaseRepresentation
bin10000011101010110101…
…101010010011000100001
311000010101111120112202121
4100131112231102120201
5122012322431024301
62223331041544241
7144500001551335
oct20352655223041
94003344515677
101131031111201
113a6738638142
12163250045081
138286a981234
143ca5683b7c5
151e649da43a1
hex10756b52621

1131031111201 has 4 divisors (see below), whose sum is σ = 1131520525504. Its totient is φ = 1130541696900.

The previous prime is 1131031111181. The next prime is 1131031111283. The reversal of 1131031111201 is 1021111301311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1131031111201 - 225 = 1130997556769 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131031111901) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244703685 + ... + 244708306.

It is an arithmetic number, because the mean of its divisors is an integer number (282880131376).

Almost surely, 21131031111201 is an apocalyptic number.

It is an amenable number.

1131031111201 is a deficient number, since it is larger than the sum of its proper divisors (489414303).

1131031111201 is an equidigital number, since it uses as much as digits as its factorization.

1131031111201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 489414302.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 1131031111201 its reverse (1021111301311), we get a palindrome (2152142412512).

The spelling of 1131031111201 in words is "one trillion, one hundred thirty-one billion, thirty-one million, one hundred eleven thousand, two hundred one".

Divisors: 1 2311 489411991 1131031111201