11310314014121 has 4 divisors (see below), whose sum is σ = 11367726775812. Its totient is φ = 11252901252432.

The previous prime is 11310314014099. The next prime is 11310314014133. The reversal of 11310314014121 is 12141041301311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6742643155600 + 4567670858521 = 2596660^2 + 2137211^2 .

It is a cyclic number.

It is not a de Polignac number, because 11310314014121 - 2²⁶ = 11310246905257 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11310314014151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28706380550 + ... + 28706380943.

It is an arithmetic number, because the mean of its divisors is an integer number (2841931693953).

Almost surely, 2^{11310314014121} is an apocalyptic number.

It is an amenable number.

11310314014121 is a deficient number, since it is larger than the sum of its proper divisors (57412761691).

11310314014121 is an equidigital number, since it uses as much as digits as its factorization.

11310314014121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57412761690.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 11310314014121 its reverse (12141041301311), we get a palindrome (23451355315432).

The spelling of 11310314014121 in words is "eleven trillion, three hundred ten billion, three hundred fourteen million, fourteen thousand, one hundred twenty-one".