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11310322213003 = 111028211110273
BaseRepresentation
bin1010010010010110001110…
…1111001110000010001011
31111001020220210122110022211
42210211203233032002023
52440302014441304003
640015520145325551
72245100220364312
oct244454357160213
944036823573284
1011310322213003
113670754036660
1213280240368b7
136407359176b8
142b15cb553279
1514931a17196d
hexa4963bce08b

11310322213003 has 4 divisors (see below), whose sum is σ = 12338533323288. Its totient is φ = 10282111102720.

The previous prime is 11310322212941. The next prime is 11310322213037. The reversal of 11310322213003 is 30031222301311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11310322213003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11310322210003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 514105555126 + ... + 514105555147.

It is an arithmetic number, because the mean of its divisors is an integer number (3084633330822).

Almost surely, 211310322213003 is an apocalyptic number.

11310322213003 is a deficient number, since it is larger than the sum of its proper divisors (1028211110285).

11310322213003 is a wasteful number, since it uses less digits than its factorization.

11310322213003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1028211110284.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 11310322213003 its reverse (30031222301311), we get a palindrome (41341544514314).

The spelling of 11310322213003 in words is "eleven trillion, three hundred ten billion, three hundred twenty-two million, two hundred thirteen thousand, three".

Divisors: 1 11 1028211110273 11310322213003