Base | Representation |
---|---|
bin | 11001101101110111101011… |
… | …110011110011001000110011 |
3 | 112211110120110112111110101012 |
4 | 121231313223303303020303 |
5 | 104311041104441431011 |
6 | 1040314541424301135 |
7 | 32552305645530050 |
oct | 3155675363631063 |
9 | 484416415443335 |
10 | 113103330030131 |
11 | 33046942227991 |
12 | 108282244717ab |
13 | 4b157a14a8a0c |
14 | 1dd0332250027 |
15 | d121256c6a8b |
hex | 66ddebcf3233 |
113103330030131 has 8 divisors (see below), whose sum is σ = 133430656625664. Its totient is φ = 93818430439560.
The previous prime is 113103330030113. The next prime is 113103330030203. The reversal of 113103330030131 is 131030033301311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113103330030131 - 246 = 42734585852467 is a prime.
It is a super-2 number, since 2×1131033300301312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113103330030097 and 113103330030106.
It is not an unprimeable number, because it can be changed into a prime (113103330038131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 260606751005 + ... + 260606751438.
It is an arithmetic number, because the mean of its divisors is an integer number (16678832078208).
Almost surely, 2113103330030131 is an apocalyptic number.
113103330030131 is a deficient number, since it is larger than the sum of its proper divisors (20327326595533).
113103330030131 is an equidigital number, since it uses as much as digits as its factorization.
113103330030131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 521213502481.
The product of its (nonzero) digits is 729, while the sum is 23.
Adding to 113103330030131 its reverse (131030033301311), we get a palindrome (244133363331442).
The spelling of 113103330030131 in words is "one hundred thirteen trillion, one hundred three billion, three hundred thirty million, thirty thousand, one hundred thirty-one".
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