1131033444131 has 8 divisors (see below), whose sum is σ = 1180644572304. Its totient is φ = 1082424561120.

The previous prime is 1131033444067. The next prime is 1131033444143. The reversal of 1131033444131 is 1314443301311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1131033444131 - 2⁶ = 1131033444067 is a prime.

It is a super-2 number, since 2×1131033444131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131033444094 and 1131033444103.

It is not an unprimeable number, because it can be changed into a prime (1131033444161) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 250558985 + ... + 250563498.

It is an arithmetic number, because the mean of its divisors is an integer number (147580571538).

Almost surely, 2^{1131033444131} is an apocalyptic number.

1131033444131 is a deficient number, since it is larger than the sum of its proper divisors (49611128173).

1131033444131 is an equidigital number, since it uses as much as digits as its factorization.

1131033444131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 501122581.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1131033444131 its reverse (1314443301311), we get a palindrome (2445476745442).

The spelling of 1131033444131 in words is "one trillion, one hundred thirty-one billion, thirty-three million, four hundred forty-four thousand, one hundred thirty-one".