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113103415115 = 522620683023
BaseRepresentation
bin110100101010101111…
…1010010011101001011
3101210221101000210120122
41221111133102131023
53323113433240430
6123543050413455
711112544110635
oct1512537223513
9353841023518
10113103415115
1143a6aa24899
1219b0613128b
13a88644c502
14568d429a55
152e1e7b7ee5
hex1a557d274b

113103415115 has 4 divisors (see below), whose sum is σ = 135724098144. Its totient is φ = 90482732088.

The previous prime is 113103415079. The next prime is 113103415129. The reversal of 113103415115 is 511514301311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511514301311 = 1339347253947.

It is a cyclic number.

It is not a de Polignac number, because 113103415115 - 28 = 113103414859 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11310341507 + ... + 11310341516.

It is an arithmetic number, because the mean of its divisors is an integer number (33931024536).

Almost surely, 2113103415115 is an apocalyptic number.

113103415115 is a deficient number, since it is larger than the sum of its proper divisors (22620683029).

113103415115 is an equidigital number, since it uses as much as digits as its factorization.

113103415115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22620683028.

The product of its (nonzero) digits is 900, while the sum is 26.

Adding to 113103415115 its reverse (511514301311), we get a palindrome (624617716426).

The spelling of 113103415115 in words is "one hundred thirteen billion, one hundred three million, four hundred fifteen thousand, one hundred fifteen".

Divisors: 1 5 22620683023 113103415115