Base | Representation |
---|---|
bin | 10101000100010011… |
… | …00100111011100001 |
3 | 1002012020102112002101 |
4 | 22202021210323201 |
5 | 141130422313040 |
6 | 5110152050401 |
7 | 550165265266 |
oct | 124211447341 |
9 | 32166375071 |
10 | 11310354145 |
11 | 4884444522 |
12 | 2237993a01 |
13 | 10b330c25c |
14 | 7941bb26d |
15 | 462e4609a |
hex | 2a2264ee1 |
11310354145 has 8 divisors (see below), whose sum is σ = 13577414760. Its totient is φ = 9044956800.
The previous prime is 11310354079. The next prime is 11310354161. The reversal of 11310354145 is 54145301311.
It can be written as a sum of positive squares in 4 ways, for example, as 5000752656 + 6309601489 = 70716^2 + 79433^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11310354145 - 27 = 11310354017 is a prime.
It is a super-2 number, since 2×113103541452 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 400806 + ... + 428095.
It is an arithmetic number, because the mean of its divisors is an integer number (1697176845).
Almost surely, 211310354145 is an apocalyptic number.
It is an amenable number.
11310354145 is a deficient number, since it is larger than the sum of its proper divisors (2267060615).
11310354145 is an equidigital number, since it uses as much as digits as its factorization.
11310354145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 831635.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 11310354145 its reverse (54145301311), we get a palindrome (65455655456).
The spelling of 11310354145 in words is "eleven billion, three hundred ten million, three hundred fifty-four thousand, one hundred forty-five".
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