1131040330131 has 8 divisors (see below), whose sum is σ = 1508059356304. Its totient is φ = 754024095360.

The previous prime is 1131040330129. The next prime is 1131040330139. The reversal of 1131040330131 is 1310330401311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1131040330131 - 2¹ = 1131040330129 is a prime.

It is a super-2 number, since 2×1131040330131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131040330098 and 1131040330107.

It is not an unprimeable number, because it can be changed into a prime (1131040330139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 583911 + ... + 1613391.

It is an arithmetic number, because the mean of its divisors is an integer number (188507419538).

Almost surely, 2^{1131040330131} is an apocalyptic number.

1131040330131 is a deficient number, since it is larger than the sum of its proper divisors (377019026173).

1131040330131 is a wasteful number, since it uses less digits than its factorization.

1131040330131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1395701.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 1131040330131 its reverse (1310330401311), we get a palindrome (2441370731442).

The spelling of 1131040330131 in words is "one trillion, one hundred thirty-one billion, forty million, three hundred thirty thousand, one hundred thirty-one".