Base | Representation |
---|---|
bin | 110100101010110011… |
… | …0111101001011110011 |
3 | 101210221111210220210222 |
4 | 1221111212331023303 |
5 | 3323114442101024 |
6 | 123543201443255 |
7 | 11112600152030 |
oct | 1512546751363 |
9 | 353844726728 |
10 | 113105425139 |
11 | 43a71077a73 |
12 | 19b0694052b |
13 | a8869a4385 |
14 | 568d7d0387 |
15 | 2e1ea6385e |
hex | 1a559bd2f3 |
113105425139 has 4 divisors (see below), whose sum is σ = 129263343024. Its totient is φ = 96947507256.
The previous prime is 113105425133. The next prime is 113105425189. The reversal of 113105425139 is 931524501311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113105425139 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113105425099 and 113105425108.
It is not an unprimeable number, because it can be changed into a prime (113105425133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8078958932 + ... + 8078958945.
It is an arithmetic number, because the mean of its divisors is an integer number (32315835756).
Almost surely, 2113105425139 is an apocalyptic number.
113105425139 is a deficient number, since it is larger than the sum of its proper divisors (16157917885).
113105425139 is an equidigital number, since it uses as much as digits as its factorization.
113105425139 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16157917884.
The product of its (nonzero) digits is 16200, while the sum is 35.
The spelling of 113105425139 in words is "one hundred thirteen billion, one hundred five million, four hundred twenty-five thousand, one hundred thirty-nine".
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