Search a number
-
+
11311011113 = 84431339691
BaseRepresentation
bin10101000100011000…
…00101010100101001
31002012021122220021112
422202030011110221
5141131104323423
65110214120105
7550204002533
oct124214052451
932167586245
1011311011113
114884853076
122238050035
1310b34ac2ac
1479430c853
15463025a78
hex2a2305529

11311011113 has 4 divisors (see below), whose sum is σ = 11312359248. Its totient is φ = 11309662980.

The previous prime is 11311011097. The next prime is 11311011121. The reversal of 11311011113 is 31111011311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11311011113 - 24 = 11311011097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11311011133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 661403 + ... + 678288.

It is an arithmetic number, because the mean of its divisors is an integer number (2828089812).

Almost surely, 211311011113 is an apocalyptic number.

It is an amenable number.

11311011113 is a deficient number, since it is larger than the sum of its proper divisors (1348135).

11311011113 is an equidigital number, since it uses as much as digits as its factorization.

11311011113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1348134.

The product of its (nonzero) digits is 9, while the sum is 14.

Adding to 11311011113 its reverse (31111011311), we get a palindrome (42422022424).

The spelling of 11311011113 in words is "eleven billion, three hundred eleven million, eleven thousand, one hundred thirteen".

Divisors: 1 8443 1339691 11311011113