Search a number
-
+
11311030113 = 331091212719
BaseRepresentation
bin10101000100011000…
…01001111101100001
31002012021200212100020
422202030021331201
5141131110430423
65110214344053
7550204112115
oct124214117541
932167625306
1011311030113
114884866379
12223805b029
1310b34b7b36
14794315745
1546302b4e3
hex2a2309f61

11311030113 has 8 divisors (see below), whose sum is σ = 15086236800. Its totient is φ = 7538255088.

The previous prime is 11311030079. The next prime is 11311030153. The reversal of 11311030113 is 31103011311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11311030113 - 29 = 11311029601 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11311030092 and 11311030101.

It is not an unprimeable number, because it can be changed into a prime (11311030153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 597033 + ... + 615686.

It is an arithmetic number, because the mean of its divisors is an integer number (1885779600).

Almost surely, 211311030113 is an apocalyptic number.

It is an amenable number.

11311030113 is a deficient number, since it is larger than the sum of its proper divisors (3775206687).

11311030113 is a wasteful number, since it uses less digits than its factorization.

11311030113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1215831.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 11311030113 its reverse (31103011311), we get a palindrome (42414041424).

It can be divided in two parts, 11 and 311030113, that multiplied together give a palindrome (3421331243).

The spelling of 11311030113 in words is "eleven billion, three hundred eleven million, thirty thousand, one hundred thirteen".

Divisors: 1 3 3109 9327 1212719 3638157 3770343371 11311030113