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113111013003 = 337703671001
BaseRepresentation
bin110100101010111110…
…0010001011010001011
3101210221220022210220220
41221111330101122023
53323122404404003
6123543521321123
711112665514132
oct1512574213213
9353856283826
10113111013003
1143a7424423a
1219b087961a3
13a887bac8c1
145690446919
152e202b9353
hex1a55f1168b

113111013003 has 4 divisors (see below), whose sum is σ = 150814684008. Its totient is φ = 75407342000.

The previous prime is 113111012977. The next prime is 113111013007. The reversal of 113111013003 is 300310111311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113111013003 - 230 = 112037271179 is a prime.

It is not an unprimeable number, because it can be changed into a prime (113111013007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18851835498 + ... + 18851835503.

It is an arithmetic number, because the mean of its divisors is an integer number (37703671002).

Almost surely, 2113111013003 is an apocalyptic number.

113111013003 is a deficient number, since it is larger than the sum of its proper divisors (37703671005).

113111013003 is an equidigital number, since it uses as much as digits as its factorization.

113111013003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37703671004.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 113111013003 its reverse (300310111311), we get a palindrome (413421124314).

The spelling of 113111013003 in words is "one hundred thirteen billion, one hundred eleven million, thirteen thousand, three".

Divisors: 1 3 37703671001 113111013003