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113111014403 = 2920031947269
BaseRepresentation
bin110100101010111110…
…0010001110000000011
3101210221220022212211202
41221111330101300003
53323122404430103
6123543521331415
711112665521202
oct1512574216003
9353856285752
10113111014403
1143a742452a2
1219b08796b6b
13a887bb042a
145690447239
152e202b9988
hex1a55f11c03

113111014403 has 8 divisors (see below), whose sum is σ = 117069872400. Its totient is φ = 109156055008.

The previous prime is 113111014349. The next prime is 113111014417. The reversal of 113111014403 is 304410111311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113111014403 - 212 = 113111010307 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113111010403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 915548 + ... + 1031721.

It is an arithmetic number, because the mean of its divisors is an integer number (14633734050).

Almost surely, 2113111014403 is an apocalyptic number.

113111014403 is a deficient number, since it is larger than the sum of its proper divisors (3958857997).

113111014403 is a wasteful number, since it uses less digits than its factorization.

113111014403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1949301.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 113111014403 its reverse (304410111311), we get a palindrome (417521125714).

The spelling of 113111014403 in words is "one hundred thirteen billion, one hundred eleven million, fourteen thousand, four hundred three".

Divisors: 1 29 2003 58087 1947269 56470801 3900379807 113111014403