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11311112114433 = 321256790234937
BaseRepresentation
bin1010010010011001001011…
…0100011101000100000001
31111001022221211222121101100
42210212102310131010001
52440310124200130213
640020130403525013
72245125621421035
oct244462264350401
944038854877340
1011311112114433
1136710199aa25a
121328204689769
13640830472bb1
142b16644101c5
151493646a1773
hexa4992d1d101

11311112114433 has 6 divisors (see below), whose sum is σ = 16338273054194. Its totient is φ = 7540741409616.

The previous prime is 11311112114429. The next prime is 11311112114437. The reversal of 11311112114433 is 33441121111311.

11311112114433 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 1 + 1 + 1 + 211 + 443 + 3 = 666.

It is an interprime number because it is at equal distance from previous prime (11311112114429) and next prime (11311112114437).

It can be written as a sum of positive squares in only one way, i.e., 9212997525264 + 2098114589169 = 3035292^2 + 1448487^2 .

It is not a de Polignac number, because 11311112114433 - 22 = 11311112114429 is a prime.

It is a super-2 number, since 2×113111121144332 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11311112114397 and 11311112114406.

It is not an unprimeable number, because it can be changed into a prime (11311112114437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 628395117460 + ... + 628395117477.

Almost surely, 211311112114433 is an apocalyptic number.

It is an amenable number.

11311112114433 is a deficient number, since it is larger than the sum of its proper divisors (5027160939761).

11311112114433 is a wasteful number, since it uses less digits than its factorization.

11311112114433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1256790234943 (or 1256790234940 counting only the distinct ones).

The product of its digits is 864, while the sum is 27.

Adding to 11311112114433 its reverse (33441121111311), we get a palindrome (44752233225744).

The spelling of 11311112114433 in words is "eleven trillion, three hundred eleven billion, one hundred twelve million, one hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 3 9 1256790234937 3770370704811 11311112114433