1131111665131 has 4 divisors (see below), whose sum is σ = 1292699045872. Its totient is φ = 969524284392.

The previous prime is 1131111665111. The next prime is 1131111665171. The reversal of 1131111665131 is 1315661111311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131111665131 - 2⁷ = 1131111665003 is a prime.

It is a super-2 number, since 2×1131111665131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131111665093 and 1131111665102.

It is not an unprimeable number, because it can be changed into a prime (1131111665111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80793690360 + ... + 80793690373.

It is an arithmetic number, because the mean of its divisors is an integer number (323174761468).

Almost surely, 2^{1131111665131} is an apocalyptic number.

1131111665131 is a deficient number, since it is larger than the sum of its proper divisors (161587380741).

1131111665131 is an equidigital number, since it uses as much as digits as its factorization.

1131111665131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161587380740.

The product of its digits is 1620, while the sum is 31.

Adding to 1131111665131 its reverse (1315661111311), we get a palindrome (2446772776442).

The spelling of 1131111665131 in words is "one trillion, one hundred thirty-one billion, one hundred eleven million, six hundred sixty-five thousand, one hundred thirty-one".