Base | Representation |
---|---|
bin | 1010010010011001100010… |
… | …1110100011001111111011 |
3 | 1111001100012202111012122210 |
4 | 2210212120232203033323 |
5 | 2440310330033331303 |
6 | 40020144304150203 |
7 | 2245131234041223 |
oct | 244463056431773 |
9 | 44040182435583 |
10 | 11311211230203 |
11 | 367106a947415 |
12 | 1328231908363 |
13 | 640847b67091 |
14 | 2b1673651083 |
15 | 14936d22e203 |
hex | a4998ba33fb |
11311211230203 has 4 divisors (see below), whose sum is σ = 15081614973608. Its totient is φ = 7540807486800.
The previous prime is 11311211230171. The next prime is 11311211230219. The reversal of 11311211230203 is 30203211211311.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 11311211230203 - 25 = 11311211230171 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11311211230203.
It is not an unprimeable number, because it can be changed into a prime (11311211230103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1885201871698 + ... + 1885201871703.
It is an arithmetic number, because the mean of its divisors is an integer number (3770403743402).
Almost surely, 211311211230203 is an apocalyptic number.
11311211230203 is a deficient number, since it is larger than the sum of its proper divisors (3770403743405).
11311211230203 is an equidigital number, since it uses as much as digits as its factorization.
11311211230203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3770403743404.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 11311211230203 its reverse (30203211211311), we get a palindrome (41514422441514).
The spelling of 11311211230203 in words is "eleven trillion, three hundred eleven billion, two hundred eleven million, two hundred thirty thousand, two hundred three".
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