113112255145 has 4 divisors (see below), whose sum is σ = 135734706180. Its totient is φ = 90489804112.

The previous prime is 113112255101. The next prime is 113112255181. The reversal of 113112255145 is 541552211311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 541552211311 = 8423 ⋅64294457.

It can be written as a sum of positive squares in 2 ways, for example, as 43698975849 + 69413279296 = 209043^2 + 263464^2 .

It is a cyclic number.

It is not a de Polignac number, because 113112255145 - 2¹¹ = 113112253097 is a prime.

It is a super-3 number, since 3×113112255145³ (a number of 34 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11311225510 + ... + 11311225519.

It is an arithmetic number, because the mean of its divisors is an integer number (33933676545).

Almost surely, 2^113112255145 is an apocalyptic number.

It is an amenable number.

113112255145 is a deficient number, since it is larger than the sum of its proper divisors (22622451035).

113112255145 is an equidigital number, since it uses as much as digits as its factorization.

113112255145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22622451034.

The product of its digits is 6000, while the sum is 31.

Adding to 113112255145 its reverse (541552211311), we get a palindrome (654664466456).

The spelling of 113112255145 in words is "one hundred thirteen billion, one hundred twelve million, two hundred fifty-five thousand, one hundred forty-five".