1131200113 has 4 divisors (see below), whose sum is σ = 1134617968. Its totient is φ = 1127782260.

The previous prime is 1131200087. The next prime is 1131200123. The reversal of 1131200113 is 3110021311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1131200113 is a prime.

It is a super-2 number, since 2×1131200113² = 2559227391302425538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1131200093 and 1131200102.

It is not an unprimeable number, because it can be changed into a prime (1131200123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1708431 + ... + 1709092.

It is an arithmetic number, because the mean of its divisors is an integer number (283654492).

Almost surely, 2^1131200113 is an apocalyptic number.

It is an amenable number.

1131200113 is a deficient number, since it is larger than the sum of its proper divisors (3417855).

1131200113 is an equidigital number, since it uses as much as digits as its factorization.

1131200113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3417854.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 1131200113 is about 33633.3184952065. The cubic root of 1131200113 is about 1041.9490426044.

Adding to 1131200113 its reverse (3110021311), we get a palindrome (4241221424).

The spelling of 1131200113 in words is "one billion, one hundred thirty-one million, two hundred thousand, one hundred thirteen".