Base | Representation |
---|---|
bin | 10000011101100000110… |
… | …101010111011000101011 |
3 | 11000010211100020211202111 |
4 | 100131200311113120223 |
5 | 122013144424013003 |
6 | 2223355551143151 |
7 | 144504133601023 |
oct | 20354065273053 |
9 | 4003740224674 |
10 | 1131201001003 |
11 | 3a6815524937 |
12 | 163298b14ab7 |
13 | 82896c25348 |
14 | 3ca71222a83 |
15 | 1e659c61e6d |
hex | 10760d5762b |
1131201001003 has 4 divisors (see below), whose sum is σ = 1132774299360. Its totient is φ = 1129627702648.
The previous prime is 1131201000961. The next prime is 1131201001043. The reversal of 1131201001003 is 3001001021311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131201001003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1131201001043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786648100 + ... + 786649537.
It is an arithmetic number, because the mean of its divisors is an integer number (283193574840).
Almost surely, 21131201001003 is an apocalyptic number.
1131201001003 is a deficient number, since it is larger than the sum of its proper divisors (1573298357).
1131201001003 is an equidigital number, since it uses as much as digits as its factorization.
1131201001003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1573298356.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 1131201001003 its reverse (3001001021311), we get a palindrome (4132202022314).
The spelling of 1131201001003 in words is "one trillion, one hundred thirty-one billion, two hundred one million, one thousand, three".
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