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113120110113 = 390127418373
BaseRepresentation
bin110100101011001111…
…0111110011000100001
3101210222112102222210220
41221112132332120201
53323132222010423
6123544444313253
711113136033253
oct1512636763041
9353875388726
10113120110113
1143a7939800a
1219b0b842829
13a889a464ca
145691733cd3
152e20eb49e3
hex1a567be621

113120110113 has 8 divisors (see below), whose sum is σ = 150828847488. Its totient is φ = 75412389744.

The previous prime is 113120110109. The next prime is 113120110123. The reversal of 113120110113 is 311011021311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 113120110113 - 22 = 113120110109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113120110092 and 113120110101.

It is not an unprimeable number, because it can be changed into a prime (113120110123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 61195 + ... + 479567.

It is an arithmetic number, because the mean of its divisors is an integer number (18853605936).

Almost surely, 2113120110113 is an apocalyptic number.

It is an amenable number.

113120110113 is a deficient number, since it is larger than the sum of its proper divisors (37708737375).

113120110113 is an equidigital number, since it uses as much as digits as its factorization.

113120110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 508503.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 113120110113 its reverse (311011021311), we get a palindrome (424131131424).

The spelling of 113120110113 in words is "one hundred thirteen billion, one hundred twenty million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 3 90127 270381 418373 1255119 37706703371 113120110113